Let a, b be nonnegative integers. Then, the solutions to 2^a - 1 = 3b^2 + 3b + 1 are limited to (1, 0), (3, 1), (7, 6). Prove or disprove.
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Let a, b be nonnegative integers. Then, the solutions to 2^a - 1 = 3b^2 + 3b + 1 are limited to (1, 0), (3, 1), (7, 6). Prove or disprove.
This article is under the CC-0 license.
Log in, or use your Fediverse account to interact with this article
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